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Re: XRAID2 calculator
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XRAID2 calculator
We previously had access to an XRAID calculator: http://rdconfigurator.netgear.com/raid/index.html
I know the ReadyNAS products are "EOL", but such resources are still useful for those of us with units that are working absolutely fine.
I found this knowledge base article, which describes the principles of RAID, but not how varied disk capacities contribute to the final XRAID capacity.
Is there a similar calculator, or perhaps, Netger might consider restoring the old one just for reference?
I did find this thread (from 2011), which I assume remains valid to do it manually:
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Re: XRAID2 calculator
@aks-2 wrote:
We previously had access to an XRAID calculator: http://rdconfigurator.netgear.com/raid/index.html
I found this knowledge base article, which describes the principles of RAID, but not how varied disk capacities contribute to the final XRAID capacity.
If you don't want to waste disk space, then with single redundancy you need to make sure the two largest disks are always the same size. For dual redundancy, you need to make sure the four largest disks are the same size.
If you follow these rules and start from a factory default, the rules for XRAID are easy to state:
- Single redundancy - "sum the disks and subtract the largest"
- Dual redundancy - "sum the disks and subtract the largest two"
The old X-RAID calculator never handled expansion, and often that created confusion when the volume size was smaller than expected after expansion..
If you want to avoid wasting space when expanding, then it is alway safe to
- Add new disks that are at least as large as the largest already in the NAS
- Single redundancy: make sure the largest two disks are the same size
- Dual redundancy: make sure the largest four disks are the same size
If you know the details of your system's RAID groups, there are other sometimes other options - but it is best to address them case by case. The formulas would be unwieldy, and they would depend on the expansion history of your volume.
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Re: XRAID2 calculator
I'll actually wipe the current volume - to get rid of ReadyCloud, and I want to reuse two 8TB disks in another NAS.
I will rebuild my RN214 with 2x4TB and 2x6TB, just wanted to understand what capacity that would offer.
I think I'll get:
- 4TB + 4TB + 6TB for data
- 6TB for redundancy
- 0TB unused
- Therefore 14TB (in HD capacity terms), and 12.7TB of usable storage in real terms.
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Re: XRAID2 calculator
@aks-2 wrote:
- Therefore 14TB (in HD capacity terms), and 12.7TB of usable storage in real terms.
14 TB, or 12.7 TiB. Both are "real", just different units for the same storage.
ReadyNAS system report TiB but use TB as the label.
@aks-2 wrote:
- 4TB + 4TB + 6TB for data
- 6TB for redundancy
This is the correct capacity. Although if you are thinking that the 6 TB redundancy is all on one disk, then that is incorrect. The parity blocks are distributed across all the disks. If you put all the parity blocks on one disk, then the write speed of that disk becomes a performance bottleneck. Plus distributing the parity blocks evens out the load on the disks in the volume.
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Re: XRAID2 calculator
Found the calculator living in an archive online
and it still works as of today June 28, 2024
Netgear - RAID Calculator (archive.org)
https://web.archive.org/web/20230130091648/https://rdconfigurator.netgear.com/raid/index.html
found it by searching archive.org for the original index page http://rdconfigurator.netgear.com/raid/index.html
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Re: XRAID2 calculator
@rfidguy wrote:
Found the calculator living in an archive online
and it still works as of today June 28, 2024
Netgear - RAID Calculator (archive.org)
https://web.archive.org/web/20230130091648/https://rdconfigurator.netgear.com/raid/index.html
found it by searching archive.org for the original index page http://rdconfigurator.netgear.com/raid/index.html
You do need to be careful with it. While it will give you the correct size for a new volume, it does not model expansion correctly. So it can give incorrect results sometimes when you are expanding to the configuration you enter.
But if you follow the basic rule to always replace a disk with one of the same size, or replace it it with one that is at least as large as the biggest disk in the array, then it works ok.
IMO it's quicker just to do the math of "sum the disks and subtract the largest".