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Simple question on CM1200
This is a simple question for many I am sure, but I could not find the answer in the CM1200 modem... That modem has 4 RJ45 ports on it - #1 goes to my router; #2 is preferred for link aggregation...
Who's your ISP?
The majority of the big ISP's only support 1 device connected to a modem.
this happens because they only assign 1 public IP address to each modem. Not multiple public IP addresses.
So for most users, the extra ports on the CM1200 are useless.
Sadly Netgear and ISP's do a poor job of explaining modems with mutiple ports.
there are a few ISP's the support multiple public IP address but they're rare and tend to be smaller ISP's.
The larger ISP's will support the ports if you pay for a business class line that supports the extra IP addresses but it costs more and isn't worth it. Reason why is you can just a switch to the router if you're needing more ports. The cost isn't worth it for consumers versus business want it for data seperation.
Who's your ISP?
The majority of the big ISP's only support 1 device connected to a modem.
this happens because they only assign 1 public IP address to each modem. Not multiple public IP addresses.
So for most users, the extra ports on the CM1200 are useless.
Sadly Netgear and ISP's do a poor job of explaining modems with mutiple ports.
there are a few ISP's the support multiple public IP address but they're rare and tend to be smaller ISP's.
The larger ISP's will support the ports if you pay for a business class line that supports the extra IP addresses but it costs more and isn't worth it. Reason why is you can just a switch to the router if you're needing more ports. The cost isn't worth it for consumers versus business want it for data seperation.
Thank you for your reply, that makes total sense! Everything works fine with the switch going thru the router, I just wondered why those ports were there. BTW my ISP is Comcast.
yeah, comcast doesn't support the mutliple public IP's unless you pay for them. I have comcast and they'll do whatever they can for extra $.